When a galvanometer is shunted with a 6 ohm resistance, the deflection is reduced to one third. If the galvanometer is further shunted with a resistance of 3 ohm, the deflection is reduced to (relative to first reading)

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one - seventh

two – third

one – fifth

one – sixth

answer is C.

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Detailed Solution

$shunt s = \frac{G}{n - 1} G is the galvanometer resistance$

$and n is no of times range is amplified$

$first tme 6 = \frac{G}{3 - 1} G = 12$

$when further shunted by 3 ohms equivalent shunt becomes \frac{6 x 3}{6 + 3} = 2$

$again 2 = \frac{12}{n - 1} n = 7$

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