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Q.

When a gas enclosed in a closed vessel was heated so as to increase its temperature by $5^{0} C$ , its pressure was seen to have increased by 2% the initial temperature of the gas was nearly

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a

$227^{0} C$

b

$23^{0} C$

c

$- 23^{0} C$

d

$250^{0} C$

answer is C.

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Detailed Solution

$\frac{P}{T} = constant$

$\begin{array}{l} \frac{P}{T} = \frac{P + 0.02 P}{T + 5} \\ T = 250 K = - 23^{0} C \end{array}$

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