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When a gas is heated from $25^{o} C$ to $50^{o} C$ at constant pressure of 1 bar, its volume:

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Increases from V to 2V

Increases from V to 1.5V

Increases from V to 1.084V

Increases from V to 1.8V

answer is C.

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Detailed Solution

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$

$T_{1} = 25 + 273 = 298 K T_{2} = 50 + 273 = 323 K \frac{V}{298} = \frac{V_{2}}{323} V_{2} = V \times \frac{323}{298} = 1.084 V$

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