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When a glass capillary tube of the radius 0.015 cm is dipped in water, the water rises to a height of 15 cm within it. Assuming the contact angle between water and glass to be $0^{o}$ , the surface tension of water is $[ρ_{w a t e r} = 1000 k g m^{- 3}, g = 9.81 m s^{- 2}]$

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$0.11 N m^{- 1}$

$0.7 N m^{- 1}$

$0.072 N m^{- 1}$

$1.1 N m^{- 1}$

answer is A.

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Detailed Solution

$T = \frac{h r d g}{2 \cos θ}$

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