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Q.

When a glass prism of refracting angle 60^o is immersed in a liquid its angle of minimum deviation is 30^o. The critical angle of glass with respect to the liquid medium is

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a

45^o

b

50^o

c

60^o

d

30^o

answer is B.

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Detailed Solution

$\frac{μ_{g}}{μ_{L}} = \frac{\sin (\frac{A + d_{m}}{2})}{\sin A / 2} = \frac{\sin 45^{o}}{\sin 30^{o}} = \sqrt{2} \Rightarrow C = 45^{o}$

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