When a liquid that is immiscible with water was steam distilled at 95.2.C at a total pressure of 748 tort the distillate contained 1.25 g of the liquid per gram of water. The vapour pressure of water is 648 toff at 95.2oC, what is the molar mass of liquid?

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When a liquid that is immiscible with water was steam distilled at 95.2.C at a total pressure of 748 tort the distillate contained 1.25 g of the liquid per gram of water. The vapour pressure of water is 648 toff at 95.2^oC, what is the molar mass of liquid?

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166 g/mol

145.8 g/mol

7.975 g/mol

None of these

answer is C.

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Detailed Solution

For two immiscible liquid;
$\begin{array}{l} P_{A}^{\circ} = P_{total} - P_{H_{2} O}^{\circ} = 748 - 648 \Rightarrow 100 \\ \frac{W_{A}}{W_{B}} = \frac{P_{A}^{\circ} M_{A}}{P_{B}^{\circ} M_{B}}; M_{A} = \frac{1 .25}{1} \times \frac{648 \times 18}{100} \\ \Rightarrow 145 .8 \end{array}$