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Q.

When a long spring is stretched by 2 cm, its potential energy is U. If the spring is stretched by 10 cm, the potential energy stored in it will be

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a

U/5

b

5U

c

10U

d

25U

answer is D.

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Detailed Solution

$\frac{U_{1}}{U_{2}} = \frac{x_{1}^{2}}{x_{2}^{2}} = \frac{4}{100} \Rightarrow U_{2} = 25 U_{1}$

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