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When a mass is suspended from the end of a wire the top end of which is attached to the roof of a lift. The extension is 'e' when the lift is stationary. If the lift moves up with a constant acceleration g/2 the extension of the wire would be ...

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3e/2

2e/3

answer is B.

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Detailed Solution

T₁ = mg
T₂ = mg + ma = mg + mg/2 = 3mg/2
Now, $e = \frac{Tl}{AY} \Rightarrow e \propto T$
$∴ \frac{e_{2}}{e_{1}} = \frac{T_{2}}{T_{1}} = \frac{3}{2} \Rightarrow e_{2} = \frac{3 e}{2}$

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