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When a mixture consisting of 10 moles of ${SO}_{2}$ and 16 moles of $O_{2}$ were passed over a catalyst, 8 mole of ${SO}_{3}$ were formed at equilibrium. The number of moles of ${SO}_{2}$ and $O_{2}$ which did not enter into reaction were :

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3, 1

2, 12

10, 3

12, 2

answer is A.

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Detailed Solution

The reaction takes place as,

${SO}_{2} + \frac{1}{2} O_{2} \to {SO}_{3} 10 16 - 2 12 8$

Here, number of moles of sulphur dioxide and oxygen which is not enter in this reaction are 2, 12.

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