When a mixture of $C u_{2} S$ and CuS is titrated with $A l {(M n O_{4})}_{3}$ in acidic medium the oxidation products of $C u_{2} S$ and CuS are $C u^{+ 2}$ and $S O_{2}$ if the molecular weight of $C u_{2} S$ ,CuS and $A l {(M n O_{4})}_{3}$ be $M_{1}, M_{2} a n d M_{3}$ respectively then which of the following statements are correct.

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Equivalent weight of $A l {(M n O_{4})}_{3}$ is $\frac{M_{3}}{15}$

Equivalent weight of CuS is $\frac{M_{2}}{5}$

Equivalent weight of $C u_{2} S$ is $\frac{M_{1}}{8}$

Equivalent weight of $A l {(M n O_{4})}_{3}$ is $\frac{M_{3}}{5}$

answer is A, D.

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Detailed Solution

n factor for $C u_{2} S$ is 8

n factor for $C u S$ is 6

n factor for $A l {(M n O_{4})}_{3}$ is 15.

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