When a mixture of Xe and F₂ in the ratio of 1 : 5 is heated at 400 °C in a sealed nickel vessel, the compound formed is

Depending on the proportions of reactants, heating Xe and ${\mathrm{F}}_2$ in a sealed nickel container at 400 °C will produce different compounds.

-$\mathrm{Xe}:{\mathrm{F}}_2$ = 2:1 will give $\mathrm{Xe}:{\mathrm{F}}_2$ as product
-$\mathrm{Xe}:{\mathrm{F}}_2$= 1:5 will give $\mathrm{Xe} : {\mathrm{F}}_4$ as product
- $\mathrm{Xe}:{\mathrm{F}}_2$ = 1:20 will give ${\mathrm{XeF}}_6$ as product