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When a point source of light is at a distance of one metre from a photo cell, the cut off voltage is found to be V. If the same source is placed at 2 m distance from photo cell, the cut off voltage will be

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V/4

V/2

V/ $\sqrt{2}$

answer is A.

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Detailed Solution

By changing distance of source, photoelectric current changes. But there is no change in stopping potential.

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