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Q.

When a silver foil (Z=47) was used in an α -ray scattering experiment, the number of α-particles scattered at 30o was found to be 200 per minute. If the silver foil is replaced by aluminum (Z = 13) foil of same thickness, the number of α-particles scattered per minute at 30o is nearly equal to:

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a

10

b

15

c

20

d

30

answer is A.

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Detailed Solution

No. of α – particles scattered at an angle 'θ ' is given by 
N=QntZ2e48πϵ02r2E2sin4⁡(θ/2)
N∝z2⇒N1N2=z1z22=200N2=47132→N2=15

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