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When a solid body is completely immersed in liquid, it displaces $50 cm³$ of liquid. If the relative density of the liquid is $0.8$ , the weight loss of the solid in the liquid is [[1]] $N$ .

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Detailed Solution

When a solid body is completely immersed in liquid, it displaces

50 cm³

of liquid. If the relative density of the liquid is

0.8

, the weight loss of the solid in the liquid is

0.4 N

.
We know that

Volume of the liquid displaced = Volume of the solid

\Rightarrow Volume of liquid displaced = 50 c m^{3}

\Rightarrow Volume of liquid displaced = 50 \times 1 0^{- 6} m^{3}

\Rightarrow Volume of liquid displaced = 0.5 \times 1 0^{- 4} m^{3}

Relative density of liquid = 0.8

Density of the liquid = Relative density \times density of water

\Rightarrow Density of the liquid = 0.8 \times 1000 kg / m^{3}

\Rightarrow Density of liquid = 800 kg / m^{3}

Loss in the weight of solid in liquid = Volume of the liquid displaced \times density \times g

= 0.5 \times 1 0^{- 4} \times 800 kg / m^{3} \times 10 m / s^{2}

= 0.4 N

Thus, the loss of weight of solid in a liquid is

0.4 N

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