When a strip of red-brown metal X is placed in a colourless solution YNO3 then metal Y is set free and a blue-coloured salt solution X(NO3)2 is formed. The liberated metal Y forms a shining white deposit on the strip of metal X. The salt X(NO3)2 is

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Zinc nitrate

Silver nitrate

Aluminium nitrate

Copper nitrate

answer is B.

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Detailed Solution

The salt X(NO3)2 is copper nitrate.
The metal X is copper (Cu), and the metal Y is silver (Ag). According to the reactivity series of metals, copper is a more reactive metal than silver. So, copper will displace silver from its silver nitrate solution. Here, the displacement reaction leads to the formation of copper nitrate [Cu(NO3)2], which makes the solution blue and the release of silver metal from its salt solution (AgNO3) in the form of a shiny white deposit. The reaction involved is:

Cu (s) + 2 AgN O_{3} (aq) \to Cu (N O_{3})_{2} (aq) + 2 Ag (s)

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