When a substance A reacts with water, it produces a combustible gas B and a solution of substance C in water. When another substance D reacts with this solution of C, it produces the same gas B on warming but D can produce gas B on reaction with dilute sulphuric acid at room temperature. A imparts a deep golden yellow colour to a smokeless flame of Bunsen burner: A, B, C and D respectively are

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$Na, H_{2}, NaOH, Zn$

$K, H_{2}, KOH, Al$

$Ca, H_{2}, Ca {(OH)}_{2}, Sn$

${CaC}_{2}, C_{2} H_{2}, Ca {(OH)}_{2}, Fe$

answer is A.

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Detailed Solution

$2 {Na}_{(s)} + 2 H_{2} O_{(l)} \to 2 {NaOH}_{(aq)} + H_{2 (g)} (A) (C) (B) {Zn}_{(s)} + 2 {NaOH}_{(aq)} \to {Na}_{2} {ZnO}_{2} + H_{2} (B) (D) {Zn}_{(s)} + H_{2} {SO}_{4 (aq)} \overset{Room temperature}{\to} {ZnSO}_{4 (aq)} + H_{2} (B) (D) Na \overset{Burn on nonlumionous flame}{\to} Golden yellow flame$