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Q.

When a uranium isotope $_{92}^{235} U$ is bombarded with a neutron, it generate $_{36}^{89} Kr$ , three neutrons and :

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a

$_{36}^{103} Kr$

b

$_{40}^{91} Zr$

c

$_{36}^{101} Kr$

d

$_{56}^{144} Ba$

answer is D.

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Detailed Solution

$_{92} U^{^{235}} +_{0} n^{1} \Rightarrow_{36} {kr}^{89} + 3_{0} n^{1} +_{56} {Ba}^{144}$

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