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When a vibrating tuning fork is placed on a sound box of a sonometer, 8 beats per second are heard when the length of the sonometer wire is kept at 101 cm or 100 cm. Then the frequency of the tuning fork is ( consider that the tension in the wire is kept constant)

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1616 Hz

1608 Hz

1632 Hz

1600 Hz

answer is B.

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Detailed Solution

$\begin{array}{l} f α \frac{1}{l} \\ \frac{f + 8}{f - 8} = \frac{101}{100} \\ f = 1608 H z \end{array}$

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