When a $25.00 mL$ volumetric flask weighing $20.340 g$ is filled partially with metal shot, the mass is $119.691 g$ . The flask is then filled to the $25.00 m L$ mark with methanol $(d = 0.791 g c m^{- 3})$ and has a total mass of $130.410 g$ . What is the density of the metal?

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$11.7 {g cm}^{- 3}$

$8.68 {g cm}^{- 3}$

$6.96 {g cm}^{- 3}$

$9.27 {g cm}^{- 3}$

answer is B.

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Detailed Solution

The density of the metal is,

Mass of metal shot $= 119.691 - 20.340 = 99.351 g$

Mass of methanol $= 130.410 - 119.691 = 10.719 g$

Vol. of methanol $= \frac{10.719}{0.791} = 13.551 mL$

Vol. of metal shot $= 25 - 13.551 = 11.449$

$∴ Density of metal = \frac{99.351}{11.449} = 8.68$

Hence, option B is correct.

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