When acetaldehyde is treated with $LiAl{H}_4,$ the product formed is

Lithium aluminium hydride is a reducing agent that makes it easier for the reacting substrate to be reduced. The addition of hydrogen is referred to as reduction. Alcohol was produced as a result of the reduction of aldehyde in the presence of lithium aluminium hydride. The following response serves as an illustration:

$C{H}_{3}CHO+LiAl{H}_4\to C{H}_{3}C{H}_{2}OH$

Hence, the correct option is (B) $C{H}_3–C{H}_2–OH$.