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When air is replaced by a dielectric medium of constant K, the maximum force of attraction between two charges, separated by a distance

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increases K times

becomes $\frac{1}{K^{2}}$ times

remains unchanged

decreases K times

answer is A.

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Detailed Solution

The force of interaction is given by $\frac{1}{4 {πKϵ}_{0}} \frac{q_{1} q_{2}}{r^{2}}$ , K is the dielectric constant.

So the force decreases K times.

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