When an alternating voltage E = Eo sin wt is applied to a circuit, a current I =Iosin(wt+𝜋/2) flows through it. The average power dissipated in the circuit is

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$E_{0} I_{0}$

$\frac{Eo Io}{\sqrt{2}}$

$E_{rms} \cdot I_{mss}$

Zero

answer is D.

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Detailed Solution

$P_{av} = E_{r . m . s} \cdot I_{r . m . s} \cdot \cos θ$
Now, here $θ = \frac{π}{2}$ $[where θ is phase difference between voltage and current]$
So, $P_{av} = E_{r.m.s} \cdot I_{r.m.s} \cdot \cos \frac{π}{2} = 0$

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