Q.

When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: h=6.6×10-34J - s

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a

3.32×10-34J - s

b

4.16×10-34J - s

c

2.08×10-34J - s

d

1.05×10-34J - s

answer is C.

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Detailed Solution

Change in Angular Momentum

The change in angular momentum is given as:

ΔL = L2 - L1 = (n2h / 2π) - (n1h / 2π)

Simplifying:

ΔL = (h / 2π)(n2 - n1)

Substitute the values:

ΔL = (6.6 × 10-34) / (2 × 3.14) × (5 - 4)

Final calculation:

ΔL = 1.05 × 10-34 J·s

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When an electron in hydrogen atom is excited, from its 4th to 5th stationary orbit, the change in angular momentum of electron is (Planck’s constant: h=6.6×10-34J - s)