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When an equimolar mixture of $C u_{2} S$ and $C u S$ is titrated with $B a {(M n O_{4})}_{2}$ in acidic medium, the final product contain $C u^{2 +}, S O_{2} and M n^{2 +}$ . If the molecular weight of $C u_{2} S, C u S a n d B a {(M n O_{4})}_{2}$ are $M_{1}, M_{2} a n d M_{3}$ respectively, then

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Equivalent weight of $C u_{2} S is \frac{M_{1}}{8}$

Equivalent weight of $C u S is \frac{M_{2}}{6}$

Equivalent weight of $B a (M n O_{4}) is \frac{M_{3}}{5}$

$C u_{2} S and CuS$ both have same equivalent weight

answer is A, B.

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Detailed Solution

n – factor of $C u_{2} S = 8$
n – factor of CuS = 6
n – factor of $B a {(M n O_{4})}_{2} = 10$

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