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When an equimolar mixture of two gases A and B $[M_{A} > M_{B}]$ is allowed to effuse through a pin. hole :

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B comes out at a faster rate

relative rate of effusion of A increases with time

initially, with equal molar ratio, rate of effusion of B is greater than rate of effusion of A.

fate of effusion of B will always be greater

answer is A, B, D.

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Detailed Solution

$\frac{r_{A}}{r_{B}} = \sqrt{\frac{m_{B}}{m_{A}}}$ This is initial rate of diffusion

So, 'B' comes out However, as time progress in relative cone. of $A ↑$ w.r.t. B. hence, rate of effusion of $A ↑$ with time.

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