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When an ideal as $(γ = 5 / 3)$ is heated under constant pressure, what percentage of given heat energy will be utilized in doing external work?

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$40 %$

$30 %$

$60 %$

$20 %$

answer is A.

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Detailed Solution

$\frac{Δ W}{Δ Q} = \frac{Δ Q - Δ U}{Δ Q} = 1 - \frac{1}{γ} = 1 - \frac{1}{\frac{5}{3}} = \frac{2}{5} \frac{Δ W}{Δ Q} \times 100 = \frac{2}{5} \times 100 \Rightarrow \frac{Δ W}{Δ Q} = 40 %$

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