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When an unknown resistance and a resistance 6Ω are connected in the left and right gaps of a meter bridge, the balance point is obtained at 50cm.If 3Ω resistance is connected in parallel to resistance in right gap, the balance point is

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decreases by 16.7cm

increases by 16.7cm

decreases by 25cm

increases by 25cm

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{x}{6} = \frac{50}{50} ∴ x = 6 Ω \\ \frac{6}{\frac{6 \times 3}{6 + 3}} = \frac{l^{1}}{100 - l^{1}}; solving, l^{1} = 75 cm \\ Δl = l^{1} - l = 75 - 50 = 25 cm = 25 cm increases \end{array}$

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