Anisole (\( C_6H_5OCH_3 \)) reacts with one equivalent of hydrogen iodide (\( HI \)) in the following manner:
- The \( HI \) cleaves the ether bond (\( -OCH_3 \)) via an SN2 mechanism.
- The reaction produces:
- \( CH_3I \) (methyl iodide) from the cleavage of the methyl group.
- \( C_6H_5OH \) (phenol) as the remaining product.