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When anisole is treated with one equivalent HI, the products formed are

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answer is C.

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Detailed Solution

Explanation:

Anisole (\( C_6H_5OCH_3 \)) reacts with one equivalent of hydrogen iodide (\( HI \)) in the following manner:

The \( HI \) cleaves the ether bond (\( -OCH_3 \)) via an SN2 mechanism.
The reaction produces:
- \( CH_3I \) (methyl iodide) from the cleavage of the methyl group.
- \( C_6H_5OH \) (phenol) as the remaining product.

Reaction Mechanism:

The reaction can be represented as:

\( C_6H_5OCH_3 + HI \rightarrow C_6H_5OH + CH_3I \)

Answer: The products formed are phenol (\( C_6H_5OH \)) and methyl iodide (\( CH_3I \)).

The correct option is c.

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