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When any solution passes through a cation exchange resin that is in acidic form, H+ ion of the resin is replaced by cations of the solution. A solution containing $0.319 g$ of an isomer with molecular formula ${CrCl}_{3} \cdot 6 H_{2} O$ is passed through a cation exchange resin in acidic form. The diluted solution requires $19 {cm}^{3}$ of $0.125 N NaOH$ The isomer is:

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triaquatrichlorochrominum (III) chloride trihydrate

hexaaquachromium (ill) chloride

pentaaquamonochlorochromium (III) chloride mono hydrate

tetraaquadichlorochromium (ill) chloride dihydrate

answer is C.

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Detailed Solution

The isomer is ${CrCl}_{3} \cdot 6 H_{2} O$ (hexaaquachromium (Ill) chloride).

Hence correct option is C.

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