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When aqueous sodium hydroxide is added to an aqueous solution of chromium (III) ions, a green blue precipitate is first formed which re-dissolves to give a green solution. This green colour is due to :

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${[Cr {(H_{2} O)}_{6}]}^{3 +}$

$[Cr (OH)_{3} {(H_{2} O)}_{3}]$

${CrO}_{4}^{2 -}$

${[Cr (OH)_{4}]}^{-}$

answer is C.

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Detailed Solution

${Cr}^{3 +} + NaOH (aq) ⟶ \underset{Green ppt .}{Cr (OH)_{3}} ↓ \overset{excess NaOH}{⟶} \underset{Green solution}{{[Cr (OH)_{4}]}^{⊖}}$

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