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When both source and listener approach each other with a velocity equal to half the velocity of sound, the change in frequency of the sound as detected by the listener is (frequency of sound = n )

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n /2

answer is B.

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Detailed Solution

$n^{1} = (\frac{V + V_{0}}{V - V_{s}}) n; V_{0} = V_{s} = \frac{V}{2}$
Apparent $n^{1} = (\frac{V + \frac{V}{2}}{V - \frac{V}{2}}) n = (\frac{\frac{3 V}{2}}{V / V}) n$
n¹ = 3n ; Apparent change
$∆$ n = n¹ - n = 3n - n = 2n

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