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When brine solution is subjected to electrolysis the gases liberated at anode and cathode are

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H₂ and Cl₂

H₂ and O₂

Cl₂ and O₂

Cl₂and H₂

answer is D.

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Detailed Solution

$2 N a C l \overset{e l e c t r o l y s i s}{\to} 2 N a^{+} + 2 C l^{-}$
At anode : $2 C l^{-} \to C l_{2} ↑ + 2 e^{-}$
At cathode : $2 H_{2} O \to 2 H^{+} + 2 O H^{-}$
$2 H^{+} + 2 e^{-} \to H_{2} ↑$
$2 N a^{+} + 2 O H^{-} \to 2 N a O H$

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