When chlorine gas passes through a concentrated solution of alkali.

$\text{ I. }{\mathrm{FeSO}}_2\text{ acts as reducing agent. }$

$\text{ II. }{\mathrm{KClO}}_3\text{ is reduced. }$

$\text{ III. Products formed are }5{\mathrm{Cl}}^{-},{\mathrm{ClO}}_3^{-}\text{and }3{\mathrm{H}}_2\mathrm{O}\text{. }$

Which of the above statements is/are correct?

When chlorine gas passes through a concentrated solution of alkali, the following chemical reaction occurs.

${\mathrm{Cl}}_2+{\mathrm{OH}}^{-}\left(\mathrm{aq}\right)⟶{\mathrm{Cl}}^{-}\left(\mathrm{aq}\right)+{\mathrm{ClO}}_3^{-}$

After balancing this equation, we have

$\underset{3 \mathrm{mol}}{3{\mathrm{Cl}}_2}+\underset{6 \mathrm{mol}}{6{\mathrm{OH}}^{-}}\left(\mathrm{aq}\right)⟶5{\mathrm{Cl}}^{-}\left(\mathrm{aq}\right)+{\mathrm{ClO}}_3^{-}\left(\mathrm{aq}\right)+3{\mathrm{H}}_2\mathrm{O}$