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When current breaks in primary coil current reaches to zero in 10^-4 second. E.M.F induced in the secondary coil is 20,000 V and mutual inductance between the coils is 5H. The maximum current in the primary before the break is

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0.2 amp

0.4 amp

4 amp

2 amp

answer is B.

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Detailed Solution

$E = M \frac{di}{dt}$

$d i = \frac{E d t}{M} = \frac{20000 \times 10^{- 4}}{5} = 0.4$

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