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Q.

When current in a coil changes from 5A to 2A in 0.1 s, an average voltage of 50V is produced. The self-inductance of the coil is

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a

0.67H

b

1.67H

c

3H

d

6H

answer is B.

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Detailed Solution

I1=5A,I2=2AΔI=25=3AΔt=0.1s,ε=50V As, ε=LΔΔt50=30.150=30LL=53=1.67H

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