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Q.

When current through a coil is 0.2A, the magnetic potential energy stored in it is $5 μ J$ . If the current in it decreases at a rate of $2 \times 10^{3} {As}^{- 1}$ then the emf induced in it is

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a

0.05V

b

5V

c

0.5V

d

5mV

answer is B.

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Detailed Solution

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$U = \frac{1}{2} L I^{2} \Rightarrow L = \frac{2 \times 5}{4 \times 10^{- 2}} \times 10^{- 6} H$

$ε = - L \frac{d I}{d t} = 250 \times 10^{- 6} \times 2 \times 10^{3} V = 0.5 V$

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