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Q.

When electromagnetic radiation of wavelength 300 nm falls on the surface of a metal, electrons are emitted with the kinetic energy of 1.68×105 J mol-1. What is the minimum energy needed to remove an electron from the metal ?  
(h=6.626×10-34Js, c=3×108 ms-1,
NA=6.022×1023 mol-1)

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a

2.31×106 mol-1

b

3.84×104 mol-1

c

3.84×1019 mol-1

d

2.31×105 mol-1

answer is D.

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Detailed Solution

Ephoton=W+K.E

Nhcλ-K.E=W

6.022×1023×6.626×10-34×3×108300×10-91.68×105

=3.99×105-1.68×105=2.31×105​J/mole

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