When equal volume of two metals are mixed together, the specific gravity of alloy is 4. When equal mass of the same two metal are mixed together, the specific gravity of the alloy is 3. Find the specific gravity of each metal.

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4 and 4

4 and 6

2 and 6

2 and 4

answer is C.

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Detailed Solution

$in case of mixture P_{mix} = \frac{m_{1} + m_{2}}{v_{1} + v_{2}} When equal volume are mixed 4 = \frac{{ve}_{1} + {ve}_{2}}{v + v} = \frac{e_{1} + e_{2}}{2} \to (1) When equal mass are mixed 3= \frac{m + m}{\frac{m}{e_{1}} + \frac{m}{e_{2}}} = \frac{2 e_{1} e_{2}}{e_{1} + e_{2}} \to (2) Therefore from (1) and (2) we get e_{1} = 2 and e_{2} = 6$

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