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Q.

When equal volumes of 0.2MAgNO3 and 1MKCN olutions were mixed then at equilibrium, concentration of Ag+ was found to be 10-6 M. While when equal volumes of 0.2 M Zn(NO3 ) 2 solution and of 1 M KCN solution were mixed then at equilibrium, concentration of Zn2+ ion was found to be 10- 12 M. Then find the equilibrium constant of following 

2Ag(CN)2(aq)+Zn2+(aq)Zn(CN)42(aq)+2Ag+(aq)

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answer is 810.

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Detailed Solution

The reaction given in the problem is given as;

Ag++2CNAg2CN20.2V1×V ~0=106V0.4V0.2V

Kf1=0.2V2V106×0.6V2V2=1079Zn2++4CNZnCN42 0.2V1×V~0V0.8V0.2V=1012=0.2V 

Kf2=0.2V21012×0.2V2V4 =1015 Kf (question) =Kf2Kf12 =10151014×81=810

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