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Q.

When equal weights of methyl alcohol and ethyl alcohol react with an excess of sodium metal, the volume of $H_{2}$ liberated is more in the case of

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a

H₂S not liberated

b

Equal in both

c

C₂H₅OH

d

CH₃OH

answer is B.

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Detailed Solution

$2 C_{2} H_{5} OH + 2 Na ⟶ 2 C_{2} H_{5} ONa + H_{2}$

$2 {CH}_{3} OH + 2 Na ⟶ 2 {CH}_{3} ONa + H_{2}$

Methanol is more acidic.

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