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Q.

When ethyl isocynide is subjected to reduction using LiAlH4, the product obtained is

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a

N-methyl ethanamine

b

N-ethyl methanamine

c

N-methyl methanamine

d

N-ethyl ethanamine

answer is A.

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Detailed Solution

C2H5NCEthyl isocyanideLiAlH4C2H5-NH-CH3N-methyl ethanamine

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