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Q.

When excess chlorine reacts with $N H_{3}$ products formed are

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a

$N H_{3} a n d N_{2}$

b

$N C l_{3} a n d H C l$

c

$N C l_{3} a n d N_{2}$

d

$N H_{4} C l a n d N_{2}$

answer is B.

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Detailed Solution

${NH}_{3} + 3 {Cl}_{2} \to \underset{nitrogen trichloride (explosive)}{{NCl}_{3}} + 3 HCl$

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