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Q.

When excess of KI reacts with 0.1M, X mL of H2O2, I2 is liberated. The liberated I2 is required 0.2M,
50 mL of hypo solution for completion of reaction to form NaI and sodium tetrathionate. Find X

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a

10 mL

b

100 mL

c

200 mL

d

50 mL

answer is D.

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Detailed Solution

H2O2 + KI →KOH + I2
l2 + Na2S2O3 →Na2S4O6 + Nal
M eq of H2O2 = m eq of KI = meq of I2 = m eq of hypo

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