When Fe0.93O is heated in presence of oxygen, it converts to Fe2O3. The number of correct statement/s from the following is___A) The equivalent weight of Fe0.93O is Molecular weight0.79B) The number of moles of Fe2+ and Fe3+ in 1 mole of Fe0.93O is 0.79 and 0.14 respectivelyC) Fe0.93O is metal deficient with lattice comprising of cubic closed packed arragement of O2- ions.D) The % composition of Fe2+ and Fe3+ in Fe0.93O is 85% and 15% respectively

Fe0.93O → Fe2O3For every 100 O atoms, 93 Fe atoms are present. If no. of Fe+2 = x, Fe+3 = 93 - xCharge balanced ⇒ 2x + 3(93 - x) = 200⇒x = 79 Fe+2 ⇒14 Fe+3A) Total change of oxidation state = 0.79 x 1 = 0.79 for 1 mole∴ Eq.wt = M.wt 0.79B) In 1 mole of Fe0.93O, 0.79 moles of Fe+2, 0.14 moles of Fe+3.C) 2Fe+3 ions replace 3Fe+3 ions. It is a metal deficiency defect D) %Fe+2=7993×100≈85%Fe+3 = 15%All statements are true

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

When Fe_0.93O is heated in presence of oxygen, it converts to Fe₂O₃. The number of correct statement/s from the following is___
A) The equivalent weight of Fe_0.93O is $\frac{Molecular weight}{0.79}$
B) The number of moles of Fe²⁺ and Fe³⁺ in 1 mole of Fe_0.93O is 0.79 and 0.14 respectively
C) Fe_0.93O is metal deficient with lattice comprising of cubic closed packed arragement of O^2- ions.
D) The % composition of Fe²⁺ and Fe³⁺ in Fe_0.93O is 85% and 15% respectively

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Fe_0.93O → Fe₂O₃
For every 100 O atoms, 93 Fe atoms are present. If no. of Fe⁺² = x, Fe⁺³ = 93 - x
Charge balanced $\Rightarrow$ 2x + 3(93 - x) = 200
$\Rightarrow$ x = 79 Fe⁺² $\Rightarrow$ 14 Fe⁺³
A) Total change of oxidation state = 0.79 x 1 = 0.79 for 1 mole
$∴ Eq.wt = \frac{M.wt}{0.79}$
B) In 1 mole of Fe_0.93O, 0.79 moles of Fe⁺², 0.14 moles of Fe⁺³.
C) 2Fe⁺³ ions replace 3Fe⁺³ ions. It is a metal deficiency defect
$D) % {Fe}^{+ 2} = \frac{79}{93} \times 100 \approx 85 %$
Fe⁺³ = 15%
All statements are true