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Q.

When forces F₁, F₂, F₃ are acting on a particle of mass m such that F₂ and F₃ are mutually perpendicular, then the particle remains stationary, if the force F₁ is now removed then acceleration of the particle is

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a

F₁ / m

b

F₁ F₃ / mF₁

c

F₂/m

d

(F₂–F₃)/m

answer is A.

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Detailed Solution

initially, for equilibrium,

$F_{1} = resultant of F_{2} and F_{3} = \sqrt{{F_{2}}^{2} + {F_{3}}^{2}}$

after removal of F₁ ,

net force on the particle = $resultant of F_{2} and F_{3} = \sqrt{{F_{2}}^{2} + {F_{3}}^{2}} = F_{1}$

$\Rightarrow a = \frac{F_{1}}{m}$

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When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary, if the force F1 is now removed then acceleration of the particle is