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Q.

When forces F1, F2, F3 are acting on a particle of mass m such that F2 and F3 are mutually perpendicular, then the particle remains stationary, if the force F1 is now removed then acceleration of the particle is 

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a

F1 / m

b

F1 F3 / mF1

c

F2/m

d

(F2–F3)/m

answer is A.

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Detailed Solution

initially, for equilibrium, 

F1=resultant of F2 and F3=F22+F32

after removal of F1 , 

net force on the particle = resultant of F2 and F3=F22+F32=F1

⇒a=F1m

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