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When forces F₁ ,F₂ ,F₃ are acting on a particle of mass m such that F₂ and F₃ are mutually perpendicular, then the particle remains stationary. If the force F₁ is now removed then the acceleration of the particle is

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F₁/m

$F_{2} F_{3} / {mF}_{1}$

$(F_{2} - F_{3}) / m$

$F_{2} / m$

answer is A.

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Detailed Solution

For equilibrium of system, $F_{1} = \sqrt{F_{2}^{2} + F_{3}^{2}}$
As $θ = 90^{\circ}$
In the absence of force F₁ ,
Acceleration $= \frac{Net force}{Mass} = \frac{\sqrt{F_{2}^{2} + F_{3}^{2}}}{m} = \frac{F_{1}}{m}$

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