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Q.

When HBr is added to CH3-CH=CH2 then the intermediate obtained is

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a

CH3−CH2−C+H2

b

CH3−CH2−C∙H2

c

CH3−C+H−CH3

d

CH3−C˙H−CH3

answer is B.

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Detailed Solution

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CH3-CH=CH2 →HBr CH3−C+H−CH3

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When HBr is added to CH3-CH=CH2 then the intermediate obtained is