When HCl is passed over one mole of $K_{2} C r_{2} O_{7},$ the no moles of $C l_{2}$ formed is _______

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answer is 3.

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Detailed Solution

$K_{2} C r_{2} O_{7} + 14 H C l \to 2 K C l + 2 C r C l_{3} + 7 H_{2} O + 3 C l_{2}$
One mole of $K_{2} C r_{2} O_{7}$ reacts HCl produces 3 moles of $C l_{2}$

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