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Q.

When Hg₂Cl₂ ionizes, the ions produced and the unpaired electrons present on the cation respectively are

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a

${Hg}_{2}^{2 +}$ and 2Cl^–, two

b

${Hg}_{2}^{2 +}$ and 2Cl^–, zero

c

${Hg}_{2}^{2 +}$ and 2Cl^–,one

d

2Hg⁺ and 2Cl^–, two

answer is D.

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Detailed Solution

${Hg}_{2} {Cl}_{2} \to {Hg}_{2}^{2 +} + 2 {Cl}^{-}$ .

Each ${Hg}^{+}$ has one unpaired electron. Hence, ${Hg}_{2}^{2 +}$ has no unpaired electron.

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