When $I_{2}$ is reacts with the mixture of KF, KCl, KBr then the products formed are respectively

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$F_{2}, C l_{2}, B r_{2}$ are formed

$F_{2}, C l_{2}$ are formed

$F_{2}$ only

None of the above

answer is D.

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Detailed Solution

Because is the weakest oxidising agent, it cannot replace $B r_{2}, C l_{2}$ (or) $F_{2}$ in $K B r, K C l$ (or) $K F$ . Hence $I_{2}$ is passed through $K F, K C l, K B r$ mixture, no reaction takes place

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